3(x-7)=8(x+1)-4

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Solution for 3(x-7)=8(x+1)-4 equation:



3(x-7)=8(x+1)-4
We move all terms to the left:
3(x-7)-(8(x+1)-4)=0
We multiply parentheses
3x-(8(x+1)-4)-21=0
We calculate terms in parentheses: -(8(x+1)-4), so:
8(x+1)-4
We multiply parentheses
8x+8-4
We add all the numbers together, and all the variables
8x+4
Back to the equation:
-(8x+4)
We get rid of parentheses
3x-8x-4-21=0
We add all the numbers together, and all the variables
-5x-25=0
We move all terms containing x to the left, all other terms to the right
-5x=25
x=25/-5
x=-5

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