3(x-72)=x+12

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Solution for 3(x-72)=x+12 equation: 



3(x-72)=x+12

We move all terms to the left:

3(x-72)-(x+12)=0

We multiply parentheses

3x-(x+12)-216=0

We get rid of parentheses

3x-x-12-216=0

We add all the numbers together, and all the variables

2x-228=0

We move all terms containing x to the left, all other terms to the right

2x=228

x=228/2

x=114

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