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3(x-8)+12=x-(12-2x)
We move all terms to the left:
3(x-8)+12-(x-(12-2x))=0
We add all the numbers together, and all the variables
3(x-8)-(x-(-2x+12))+12=0
We multiply parentheses
3x-(x-(-2x+12))-24+12=0
We calculate terms in parentheses: -(x-(-2x+12)), so:We add all the numbers together, and all the variables
x-(-2x+12)
We get rid of parentheses
x+2x-12
We add all the numbers together, and all the variables
3x-12
Back to the equation:
-(3x-12)
3x-(3x-12)-12=0
We get rid of parentheses
3x-3x+12-12=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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