3(x-8)+6(2-x)-(x-2)=x

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Solution for 3(x-8)+6(2-x)-(x-2)=x equation: 



3(x-8)+6(2-x)-(x-2)=x

We move all terms to the left:

3(x-8)+6(2-x)-(x-2)-(x)=0

We add all the numbers together, and all the variables

3(x-8)+6(-1x+2)-(x-2)-x=0

We add all the numbers together, and all the variables

-1x+3(x-8)+6(-1x+2)-(x-2)=0

We multiply parentheses

-1x+3x-6x-(x-2)-24+12=0

We get rid of parentheses

-1x+3x-6x-x+2-24+12=0

We add all the numbers together, and all the variables

-5x-10=0

We move all terms containing x to the left, all other terms to the right

-5x=10

x=10/-5

x=-2

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