3(x-8)-5=9(x+2)+2+1

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Solution for 3(x-8)-5=9(x+2)+2+1 equation: 



3(x-8)-5=9(x+2)+2+1

We move all terms to the left:

3(x-8)-5-(9(x+2)+2+1)=0

We multiply parentheses

3x-(9(x+2)+2+1)-24-5=0



We calculate terms in parentheses: -(9(x+2)+2+1), so:

9(x+2)+2+1

We add all the numbers together, and all the variables

9(x+2)+3

We multiply parentheses

9x+18+3

We add all the numbers together, and all the variables

9x+21

Back to the equation:

-(9x+21)



We add all the numbers together, and all the variables

3x-(9x+21)-29=0

We get rid of parentheses

3x-9x-21-29=0

We add all the numbers together, and all the variables

-6x-50=0

We move all terms containing x to the left, all other terms to the right

-6x=50

x=50/-6

x=-8+1/3

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