3(x-8)=7(x+1)=

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Solution for 3(x-8)=7(x+1)= equation: 



3(x-8)=7(x+1)=

We move all terms to the left:

3(x-8)-(7(x+1))=0

We multiply parentheses

3x-(7(x+1))-24=0



We calculate terms in parentheses: -(7(x+1)), so:

7(x+1)

We multiply parentheses

7x+7

Back to the equation:

-(7x+7)



We get rid of parentheses

3x-7x-7-24=0

We add all the numbers together, and all the variables

-4x-31=0

We move all terms containing x to the left, all other terms to the right

-4x=31

x=31/-4

x=-7+3/4

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