3(x-9)+x2=4x+x2+16

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Solution for 3(x-9)+x2=4x+x2+16 equation:



3(x-9)+x2=4x+x2+16
We move all terms to the left:
3(x-9)+x2-(4x+x2+16)=0
We add all the numbers together, and all the variables
-(+4x+x^2+16)+3(x-9)+x2=0
We add all the numbers together, and all the variables
x^2-(+4x+x^2+16)+3(x-9)=0
We multiply parentheses
x^2-(+4x+x^2+16)+3x-27=0
We get rid of parentheses
x^2-x^2-4x+3x-16-27=0
We add all the numbers together, and all the variables
-1x-43=0
We move all terms containing x to the left, all other terms to the right
-x=43
x=43/-1
x=-43

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