3(x2)+1=3x-5

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Solution for 3(x2)+1=3x-5 equation: 



3(x2)+1=3x-5

We move all terms to the left:

3(x2)+1-(3x-5)=0

We add all the numbers together, and all the variables

3x^2-(3x-5)+1=0

We get rid of parentheses

3x^2-3x+5+1=0

We add all the numbers together, and all the variables

3x^2-3x+6=0

a = 3; b = -3; c = +6;
Δ = b2-4ac
Δ = -32-4·3·6
Δ = -63
Delta is less than zero, so there is no solution for the equation

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