3(x2)+8=2(x+3)

Solution for 3(x2)+8=2(x+3) equation:

3(x2)+8=2(x+3)

We move all terms to the left:

3(x2)+8-(2(x+3))=0

We add all the numbers together, and all the variables

3x^2-(2(x+3))+8=0


We calculate terms in parentheses: -(2(x+3)), so:

2(x+3)

We multiply parentheses

2x+6

Back to the equation:

-(2x+6)


We get rid of parentheses

3x^2-2x-6+8=0

We add all the numbers together, and all the variables

3x^2-2x+2=0

a = 3; b = -2; c = +2;
Δ = b2-4ac
Δ = -22-4·3·2
Δ = -20
Delta is less than zero, so there is no solution for the equation