3(x2)=x+8+2x

Solution for 3(x2)=x+8+2x equation:

3(x2)=x+8+2x

We move all terms to the left:

3(x2)-(x+8+2x)=0

We add all the numbers together, and all the variables

3x2-(3x+8)=0

We add all the numbers together, and all the variables

3x^2-(3x+8)=0

We get rid of parentheses

3x^2-3x-8=0

a = 3; b = -3; c = -8;
Δ = b2-4ac
Δ = -32-4·3·(-8)
Δ = 105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-\sqrt{105}}{2*3}=\frac{3-\sqrt{105}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+\sqrt{105}}{2*3}=\frac{3+\sqrt{105}}{6}
$