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3(x2-4)-18=(x-1)2
We move all terms to the left:
3(x2-4)-18-((x-1)2)=0
We add all the numbers together, and all the variables
3(+x^2-4)-((x-1)2)-18=0
We multiply parentheses
3x^2-((x-1)2)-12-18=0
We calculate terms in parentheses: -((x-1)2), so:We add all the numbers together, and all the variables
(x-1)2
We multiply parentheses
2x-2
Back to the equation:
-(2x-2)
3x^2-(2x-2)-30=0
We get rid of parentheses
3x^2-2x+2-30=0
We add all the numbers together, and all the variables
3x^2-2x-28=0
a = 3; b = -2; c = -28;
Δ = b2-4ac
Δ = -22-4·3·(-28)
Δ = 340
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{340}=\sqrt{4*85}=\sqrt{4}*\sqrt{85}=2\sqrt{85}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{85}}{2*3}=\frac{2-2\sqrt{85}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{85}}{2*3}=\frac{2+2\sqrt{85}}{6} $
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