3(y)+4(y-2)=116

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Solution for 3(y)+4(y-2)=116 equation: 



3(y)+4(y-2)=116

We move all terms to the left:

3(y)+4(y-2)-(116)=0

We multiply parentheses

3y+4y-8-116=0

We add all the numbers together, and all the variables

7y-124=0

We move all terms containing y to the left, all other terms to the right

7y=124

y=124/7

y=17+5/7

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