3(y+-10)=42

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Solution for 3(y+-10)=42 equation: 



3(y+-10)=42

We move all terms to the left:

3(y+-10)-(42)=0

We add all the numbers together, and all the variables

3(y-10)-42=0

We multiply parentheses

3y-30-42=0

We add all the numbers together, and all the variables

3y-72=0

We move all terms containing y to the left, all other terms to the right

3y=72

y=72/3

y=24

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