3(y+1)+(y+2)=24

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Solution for 3(y+1)+(y+2)=24 equation: 



3(y+1)+(y+2)=24

We move all terms to the left:

3(y+1)+(y+2)-(24)=0

We multiply parentheses

3y+(y+2)+3-24=0

We get rid of parentheses

3y+y+2+3-24=0

We add all the numbers together, and all the variables

4y-19=0

We move all terms containing y to the left, all other terms to the right

4y=19

y=19/4

y=4+3/4

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