3(y+1)+2y=5(y-1)+5

Solution for 3(y+1)+2y=5(y-1)+5 equation:

Simplifying
3(y + 1) + 2y = 5(y + -1) + 5

Reorder the terms:
3(1 + y) + 2y = 5(y + -1) + 5
(1 * 3 + y * 3) + 2y = 5(y + -1) + 5
(3 + 3y) + 2y = 5(y + -1) + 5

Combine like terms: 3y + 2y = 5y
3 + 5y = 5(y + -1) + 5

Reorder the terms:
3 + 5y = 5(-1 + y) + 5
3 + 5y = (-1 * 5 + y * 5) + 5
3 + 5y = (-5 + 5y) + 5

Reorder the terms:
3 + 5y = -5 + 5 + 5y

Combine like terms: -5 + 5 = 0
3 + 5y = 0 + 5y
3 + 5y = 5y

Add '-5y' to each side of the equation.
3 + 5y + -5y = 5y + -5y

Combine like terms: 5y + -5y = 0
3 + 0 = 5y + -5y
3 = 5y + -5y

Combine like terms: 5y + -5y = 0
3 = 0

Solving
3 = 0

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.