3(y+1)+2y=5(y-1)=5

Solution for 3(y+1)+2y=5(y-1)=5 equation:

3(y+1)+2y=5(y-1)=5

We move all terms to the left:

3(y+1)+2y-(5(y-1))=0

We add all the numbers together, and all the variables

2y+3(y+1)-(5(y-1))=0

We multiply parentheses

2y+3y-(5(y-1))+3=0


We calculate terms in parentheses: -(5(y-1)), so:

5(y-1)

We multiply parentheses

5y-5

Back to the equation:

-(5y-5)


We add all the numbers together, and all the variables

5y-(5y-5)+3=0

We get rid of parentheses

5y-5y+5+3=0

We add all the numbers together, and all the variables

8!=0

There is no solution for this equation