3(y+1)+2y=5(y-1+5)

Solution for 3(y+1)+2y=5(y-1+5) equation:

Simplifying
3(y + 1) + 2y = 5(y + -1 + 5)

Reorder the terms:
3(1 + y) + 2y = 5(y + -1 + 5)
(1 * 3 + y * 3) + 2y = 5(y + -1 + 5)
(3 + 3y) + 2y = 5(y + -1 + 5)

Combine like terms: 3y + 2y = 5y
3 + 5y = 5(y + -1 + 5)

Reorder the terms:
3 + 5y = 5(-1 + 5 + y)

Combine like terms: -1 + 5 = 4
3 + 5y = 5(4 + y)
3 + 5y = (4 * 5 + y * 5)
3 + 5y = (20 + 5y)

Add '-5y' to each side of the equation.
3 + 5y + -5y = 20 + 5y + -5y

Combine like terms: 5y + -5y = 0
3 + 0 = 20 + 5y + -5y
3 = 20 + 5y + -5y

Combine like terms: 5y + -5y = 0
3 = 20 + 0
3 = 20

Solving
3 = 20

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.