3(y+1)+4y=3(2y-1)+8

Solution for 3(y+1)+4y=3(2y-1)+8 equation:

Simplifying
3(y + 1) + 4y = 3(2y + -1) + 8

Reorder the terms:
3(1 + y) + 4y = 3(2y + -1) + 8
(1 * 3 + y * 3) + 4y = 3(2y + -1) + 8
(3 + 3y) + 4y = 3(2y + -1) + 8

Combine like terms: 3y + 4y = 7y
3 + 7y = 3(2y + -1) + 8

Reorder the terms:
3 + 7y = 3(-1 + 2y) + 8
3 + 7y = (-1 * 3 + 2y * 3) + 8
3 + 7y = (-3 + 6y) + 8

Reorder the terms:
3 + 7y = -3 + 8 + 6y

Combine like terms: -3 + 8 = 5
3 + 7y = 5 + 6y

Solving
3 + 7y = 5 + 6y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-6y' to each side of the equation.
3 + 7y + -6y = 5 + 6y + -6y

Combine like terms: 7y + -6y = 1y
3 + 1y = 5 + 6y + -6y

Combine like terms: 6y + -6y = 0
3 + 1y = 5 + 0
3 + 1y = 5

Add '-3' to each side of the equation.
3 + -3 + 1y = 5 + -3

Combine like terms: 3 + -3 = 0
0 + 1y = 5 + -3
1y = 5 + -3

Combine like terms: 5 + -3 = 2
1y = 2

Divide each side by '1'.
y = 2

Simplifying
y = 2