3(y+1)+7/5=5

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Solution for 3(y+1)+7/5=5 equation: 



3(y+1)+7/5=5

We move all terms to the left:

3(y+1)+7/5-(5)=0

determiningTheFunctionDomain
3(y+1)-5+7/5=0

We multiply parentheses

3y+3-5+7/5=0

We multiply all the terms by the denominator


3y*5+7+3*5-5*5=0

We add all the numbers together, and all the variables

3y*5-3=0

Wy multiply elements

15y-3=0

We move all terms containing y to the left, all other terms to the right

15y=3

y=3/15

y=1/5

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