3(y+1)-20=2(y-5)

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Solution for 3(y+1)-20=2(y-5) equation:


Simplifying
3(y + 1) + -20 = 2(y + -5)

Reorder the terms:
3(1 + y) + -20 = 2(y + -5)
(1 * 3 + y * 3) + -20 = 2(y + -5)
(3 + 3y) + -20 = 2(y + -5)

Reorder the terms:
3 + -20 + 3y = 2(y + -5)

Combine like terms: 3 + -20 = -17
-17 + 3y = 2(y + -5)

Reorder the terms:
-17 + 3y = 2(-5 + y)
-17 + 3y = (-5 * 2 + y * 2)
-17 + 3y = (-10 + 2y)

Solving
-17 + 3y = -10 + 2y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-2y' to each side of the equation.
-17 + 3y + -2y = -10 + 2y + -2y

Combine like terms: 3y + -2y = 1y
-17 + 1y = -10 + 2y + -2y

Combine like terms: 2y + -2y = 0
-17 + 1y = -10 + 0
-17 + 1y = -10

Add '17' to each side of the equation.
-17 + 17 + 1y = -10 + 17

Combine like terms: -17 + 17 = 0
0 + 1y = -10 + 17
1y = -10 + 17

Combine like terms: -10 + 17 = 7
1y = 7

Divide each side by '1'.
y = 7

Simplifying
y = 7

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