3(y+1)-5=3y-2

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Solution for 3(y+1)-5=3y-2 equation: 


Simplifying
3(y + 1) + -5 = 3y + -2

Reorder the terms:
3(1 + y) + -5 = 3y + -2
(1 * 3 + y * 3) + -5 = 3y + -2
(3 + 3y) + -5 = 3y + -2

Reorder the terms:
3 + -5 + 3y = 3y + -2

Combine like terms: 3 + -5 = -2
-2 + 3y = 3y + -2

Reorder the terms:
-2 + 3y = -2 + 3y

Add '2' to each side of the equation.
-2 + 2 + 3y = -2 + 2 + 3y

Combine like terms: -2 + 2 = 0
0 + 3y = -2 + 2 + 3y
3y = -2 + 2 + 3y

Combine like terms: -2 + 2 = 0
3y = 0 + 3y
3y = 3y

Add '-3y' to each side of the equation.
3y + -3y = 3y + -3y

Combine like terms: 3y + -3y = 0
0 = 3y + -3y

Combine like terms: 3y + -3y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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