3(y+1)=-(4-2y)

Solution for 3(y+1)=-(4-2y) equation:

3(y+1)=-(4-2y)

We move all terms to the left:

3(y+1)-(-(4-2y))=0

We add all the numbers together, and all the variables

3(y+1)-(-(-2y+4))=0

We multiply parentheses

3y-(-(-2y+4))+3=0


We calculate terms in parentheses: -(-(-2y+4)), so:

-(-2y+4)

We get rid of parentheses

2y-4

Back to the equation:

-(2y-4)


We get rid of parentheses

3y-2y+4+3=0

We add all the numbers together, and all the variables

y+7=0

We move all terms containing y to the left, all other terms to the right

y=-7