3(y+1)=-2y-32

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Solution for 3(y+1)=-2y-32 equation: 



3(y+1)=-2y-32

We move all terms to the left:

3(y+1)-(-2y-32)=0

We multiply parentheses

3y-(-2y-32)+3=0

We get rid of parentheses

3y+2y+32+3=0

We add all the numbers together, and all the variables

5y+35=0

We move all terms containing y to the left, all other terms to the right

5y=-35

y=-35/5

y=-7

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