3(y+1)=19-5y

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Solution for 3(y+1)=19-5y equation: 



3(y+1)=19-5y

We move all terms to the left:

3(y+1)-(19-5y)=0

We add all the numbers together, and all the variables

3(y+1)-(-5y+19)=0

We multiply parentheses

3y-(-5y+19)+3=0

We get rid of parentheses

3y+5y-19+3=0

We add all the numbers together, and all the variables

8y-16=0

We move all terms containing y to the left, all other terms to the right

8y=16

y=16/8

y=2

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