3(y+1)=2(2y-6)

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Solution for 3(y+1)=2(2y-6) equation: 



3(y+1)=2(2y-6)

We move all terms to the left:

3(y+1)-(2(2y-6))=0

We multiply parentheses

3y-(2(2y-6))+3=0



We calculate terms in parentheses: -(2(2y-6)), so:

2(2y-6)

We multiply parentheses

4y-12

Back to the equation:

-(4y-12)



We get rid of parentheses

3y-4y+12+3=0

We add all the numbers together, and all the variables

-1y+15=0

We move all terms containing y to the left, all other terms to the right

-y=-15

y=-15/-1

y=+15

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