3(y+1)=2(y-6)

Solution for 3(y+1)=2(y-6) equation:

Simplifying
3(y + 1) = 2(y + -6)

Reorder the terms:
3(1 + y) = 2(y + -6)
(1 * 3 + y * 3) = 2(y + -6)
(3 + 3y) = 2(y + -6)

Reorder the terms:
3 + 3y = 2(-6 + y)
3 + 3y = (-6 * 2 + y * 2)
3 + 3y = (-12 + 2y)

Solving
3 + 3y = -12 + 2y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-2y' to each side of the equation.
3 + 3y + -2y = -12 + 2y + -2y

Combine like terms: 3y + -2y = 1y
3 + 1y = -12 + 2y + -2y

Combine like terms: 2y + -2y = 0
3 + 1y = -12 + 0
3 + 1y = -12

Add '-3' to each side of the equation.
3 + -3 + 1y = -12 + -3

Combine like terms: 3 + -3 = 0
0 + 1y = -12 + -3
1y = -12 + -3

Combine like terms: -12 + -3 = -15
1y = -15

Divide each side by '1'.
y = -15

Simplifying
y = -15