3(y+1)=4(y-7)

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Solution for 3(y+1)=4(y-7) equation: 



3(y+1)=4(y-7)

We move all terms to the left:

3(y+1)-(4(y-7))=0

We multiply parentheses

3y-(4(y-7))+3=0



We calculate terms in parentheses: -(4(y-7)), so:

4(y-7)

We multiply parentheses

4y-28

Back to the equation:

-(4y-28)



We get rid of parentheses

3y-4y+28+3=0

We add all the numbers together, and all the variables

-1y+31=0

We move all terms containing y to the left, all other terms to the right

-y=-31

y=-31/-1

y=+31

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