3(y+1)=5(y+3)+10

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Solution for 3(y+1)=5(y+3)+10 equation: 


Simplifying
3(y + 1) = 5(y + 3) + 10

Reorder the terms:
3(1 + y) = 5(y + 3) + 10
(1 * 3 + y * 3) = 5(y + 3) + 10
(3 + 3y) = 5(y + 3) + 10

Reorder the terms:
3 + 3y = 5(3 + y) + 10
3 + 3y = (3 * 5 + y * 5) + 10
3 + 3y = (15 + 5y) + 10

Reorder the terms:
3 + 3y = 15 + 10 + 5y

Combine like terms: 15 + 10 = 25
3 + 3y = 25 + 5y

Solving
3 + 3y = 25 + 5y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-5y' to each side of the equation.
3 + 3y + -5y = 25 + 5y + -5y

Combine like terms: 3y + -5y = -2y
3 + -2y = 25 + 5y + -5y

Combine like terms: 5y + -5y = 0
3 + -2y = 25 + 0
3 + -2y = 25

Add '-3' to each side of the equation.
3 + -3 + -2y = 25 + -3

Combine like terms: 3 + -3 = 0
0 + -2y = 25 + -3
-2y = 25 + -3

Combine like terms: 25 + -3 = 22
-2y = 22

Divide each side by '-2'.
y = -11

Simplifying
y = -11

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