3(y+1)=6(1-y)+6

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Solution for 3(y+1)=6(1-y)+6 equation: 



3(y+1)=6(1-y)+6

We move all terms to the left:

3(y+1)-(6(1-y)+6)=0

We add all the numbers together, and all the variables

3(y+1)-(6(-1y+1)+6)=0

We multiply parentheses

3y-(6(-1y+1)+6)+3=0



We calculate terms in parentheses: -(6(-1y+1)+6), so:

6(-1y+1)+6

We multiply parentheses

-6y+6+6

We add all the numbers together, and all the variables

-6y+12

Back to the equation:

-(-6y+12)



We get rid of parentheses

3y+6y-12+3=0

We add all the numbers together, and all the variables

9y-9=0

We move all terms containing y to the left, all other terms to the right

9y=9

y=9/9

y=1

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