3(y+1)=7(y-2)-3

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Solution for 3(y+1)=7(y-2)-3 equation: 



3(y+1)=7(y-2)-3

We move all terms to the left:

3(y+1)-(7(y-2)-3)=0

We multiply parentheses

3y-(7(y-2)-3)+3=0



We calculate terms in parentheses: -(7(y-2)-3), so:

7(y-2)-3

We multiply parentheses

7y-14-3

We add all the numbers together, and all the variables

7y-17

Back to the equation:

-(7y-17)



We get rid of parentheses

3y-7y+17+3=0

We add all the numbers together, and all the variables

-4y+20=0

We move all terms containing y to the left, all other terms to the right

-4y=-20

y=-20/-4

y=+5

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