3(y+11)=6(2y-3)

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Solution for 3(y+11)=6(2y-3) equation: 



3(y+11)=6(2y-3)

We move all terms to the left:

3(y+11)-(6(2y-3))=0

We multiply parentheses

3y-(6(2y-3))+33=0



We calculate terms in parentheses: -(6(2y-3)), so:

6(2y-3)

We multiply parentheses

12y-18

Back to the equation:

-(12y-18)



We get rid of parentheses

3y-12y+18+33=0

We add all the numbers together, and all the variables

-9y+51=0

We move all terms containing y to the left, all other terms to the right

-9y=-51

y=-51/-9

y=5+2/3

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