3(y+12)=8y+1

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Solution for 3(y+12)=8y+1 equation: 



3(y+12)=8y+1

We move all terms to the left:

3(y+12)-(8y+1)=0

We multiply parentheses

3y-(8y+1)+36=0

We get rid of parentheses

3y-8y-1+36=0

We add all the numbers together, and all the variables

-5y+35=0

We move all terms containing y to the left, all other terms to the right

-5y=-35

y=-35/-5

y=+7

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