3(y+12)=y-4

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Solution for 3(y+12)=y-4 equation: 



3(y+12)=y-4

We move all terms to the left:

3(y+12)-(y-4)=0

We multiply parentheses

3y-(y-4)+36=0

We get rid of parentheses

3y-y+4+36=0

We add all the numbers together, and all the variables

2y+40=0

We move all terms containing y to the left, all other terms to the right

2y=-40

y=-40/2

y=-20

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