3(y+2)+(y-3)=15

Solution for 3(y+2)+(y-3)=15 equation:

Simplifying
3(y + 2) + (y + -3) = 15

Reorder the terms:
3(2 + y) + (y + -3) = 15
(2 * 3 + y * 3) + (y + -3) = 15
(6 + 3y) + (y + -3) = 15

Reorder the terms:
6 + 3y + (-3 + y) = 15

Remove parenthesis around (-3 + y)
6 + 3y + -3 + y = 15

Reorder the terms:
6 + -3 + 3y + y = 15

Combine like terms: 6 + -3 = 3
3 + 3y + y = 15

Combine like terms: 3y + y = 4y
3 + 4y = 15

Solving
3 + 4y = 15

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 4y = 15 + -3

Combine like terms: 3 + -3 = 0
0 + 4y = 15 + -3
4y = 15 + -3

Combine like terms: 15 + -3 = 12
4y = 12

Divide each side by '4'.
y = 3

Simplifying
y = 3