3(y+2)+1=-5(3+2y

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Solution for 3(y+2)+1=-5(3+2y equation: 



3(y+2)+1=-5(3+2y

We move all terms to the left:

3(y+2)+1-(-5(3+2y)=0

We add all the numbers together, and all the variables

3(y+2)-(-5(2y+3)+1=0

We multiply parentheses

3y-(-5(2y+3)+1+6=0

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