3(y+2)+1=-5(3+2y)

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Solution for 3(y+2)+1=-5(3+2y) equation: 



3(y+2)+1=-5(3+2y)

We move all terms to the left:

3(y+2)+1-(-5(3+2y))=0

We add all the numbers together, and all the variables

3(y+2)-(-5(2y+3))+1=0

We multiply parentheses

3y-(-5(2y+3))+6+1=0



We calculate terms in parentheses: -(-5(2y+3)), so:

-5(2y+3)

We multiply parentheses

-10y-15

Back to the equation:

-(-10y-15)



We add all the numbers together, and all the variables

3y-(-10y-15)+7=0

We get rid of parentheses

3y+10y+15+7=0

We add all the numbers together, and all the variables

13y+22=0

We move all terms containing y to the left, all other terms to the right

13y=-22

y=-22/13

y=-1+9/13

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