3(y+2)+2(y-3)=-3=

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Solution for 3(y+2)+2(y-3)=-3= equation: 



3(y+2)+2(y-3)=-3=

We move all terms to the left:

3(y+2)+2(y-3)-(-3)=0

We add all the numbers together, and all the variables

3(y+2)+2(y-3)+3=0

We multiply parentheses

3y+2y+6-6+3=0

We add all the numbers together, and all the variables

5y+3=0

We move all terms containing y to the left, all other terms to the right

5y=-3

y=-3/5

y=-3/5

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