3(y+2)+2+(y-3)=15

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Solution for 3(y+2)+2+(y-3)=15 equation:



3(y+2)+2+(y-3)=15
We move all terms to the left:
3(y+2)+2+(y-3)-(15)=0
We add all the numbers together, and all the variables
3(y+2)+(y-3)-13=0
We multiply parentheses
3y+(y-3)+6-13=0
We get rid of parentheses
3y+y-3+6-13=0
We add all the numbers together, and all the variables
4y-10=0
We move all terms containing y to the left, all other terms to the right
4y=10
y=10/4
y=2+1/2

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