3(y+2)+2+(y-3)=15

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Solution for 3(y+2)+2+(y-3)=15 equation: 



3(y+2)+2+(y-3)=15

We move all terms to the left:

3(y+2)+2+(y-3)-(15)=0

We add all the numbers together, and all the variables

3(y+2)+(y-3)-13=0

We multiply parentheses

3y+(y-3)+6-13=0

We get rid of parentheses

3y+y-3+6-13=0

We add all the numbers together, and all the variables

4y-10=0

We move all terms containing y to the left, all other terms to the right

4y=10

y=10/4

y=2+1/2

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