3(y+2)+2y=7(1-4y)+9

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Solution for 3(y+2)+2y=7(1-4y)+9 equation: 



3(y+2)+2y=7(1-4y)+9

We move all terms to the left:

3(y+2)+2y-(7(1-4y)+9)=0

We add all the numbers together, and all the variables

3(y+2)+2y-(7(-4y+1)+9)=0

We add all the numbers together, and all the variables

2y+3(y+2)-(7(-4y+1)+9)=0

We multiply parentheses

2y+3y-(7(-4y+1)+9)+6=0



We calculate terms in parentheses: -(7(-4y+1)+9), so:

7(-4y+1)+9

We multiply parentheses

-28y+7+9

We add all the numbers together, and all the variables

-28y+16

Back to the equation:

-(-28y+16)



We add all the numbers together, and all the variables

5y-(-28y+16)+6=0

We get rid of parentheses

5y+28y-16+6=0

We add all the numbers together, and all the variables

33y-10=0

We move all terms containing y to the left, all other terms to the right

33y=10

y=10/33

y=10/33

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