3(y+2)+3(y-3)=15

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Solution for 3(y+2)+3(y-3)=15 equation:


Simplifying
3(y + 2) + 3(y + -3) = 15

Reorder the terms:
3(2 + y) + 3(y + -3) = 15
(2 * 3 + y * 3) + 3(y + -3) = 15
(6 + 3y) + 3(y + -3) = 15

Reorder the terms:
6 + 3y + 3(-3 + y) = 15
6 + 3y + (-3 * 3 + y * 3) = 15
6 + 3y + (-9 + 3y) = 15

Reorder the terms:
6 + -9 + 3y + 3y = 15

Combine like terms: 6 + -9 = -3
-3 + 3y + 3y = 15

Combine like terms: 3y + 3y = 6y
-3 + 6y = 15

Solving
-3 + 6y = 15

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + 6y = 15 + 3

Combine like terms: -3 + 3 = 0
0 + 6y = 15 + 3
6y = 15 + 3

Combine like terms: 15 + 3 = 18
6y = 18

Divide each side by '6'.
y = 3

Simplifying
y = 3

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