3(y+2)+4=10+3y

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Solution for 3(y+2)+4=10+3y equation: 



3(y+2)+4=10+3y

We move all terms to the left:

3(y+2)+4-(10+3y)=0

We add all the numbers together, and all the variables

3(y+2)-(3y+10)+4=0

We multiply parentheses

3y-(3y+10)+6+4=0

We get rid of parentheses

3y-3y-10+6+4=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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