3(y+2)+4=5(y-1)+1

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Solution for 3(y+2)+4=5(y-1)+1 equation: 



3(y+2)+4=5(y-1)+1

We move all terms to the left:

3(y+2)+4-(5(y-1)+1)=0

We multiply parentheses

3y-(5(y-1)+1)+6+4=0



We calculate terms in parentheses: -(5(y-1)+1), so:

5(y-1)+1

We multiply parentheses

5y-5+1

We add all the numbers together, and all the variables

5y-4

Back to the equation:

-(5y-4)



We add all the numbers together, and all the variables

3y-(5y-4)+10=0

We get rid of parentheses

3y-5y+4+10=0

We add all the numbers together, and all the variables

-2y+14=0

We move all terms containing y to the left, all other terms to the right

-2y=-14

y=-14/-2

y=+7

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