3(y+2)+4=5(y-1)+2

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Solution for 3(y+2)+4=5(y-1)+2 equation: 



3(y+2)+4=5(y-1)+2

We move all terms to the left:

3(y+2)+4-(5(y-1)+2)=0

We multiply parentheses

3y-(5(y-1)+2)+6+4=0



We calculate terms in parentheses: -(5(y-1)+2), so:

5(y-1)+2

We multiply parentheses

5y-5+2

We add all the numbers together, and all the variables

5y-3

Back to the equation:

-(5y-3)



We add all the numbers together, and all the variables

3y-(5y-3)+10=0

We get rid of parentheses

3y-5y+3+10=0

We add all the numbers together, and all the variables

-2y+13=0

We move all terms containing y to the left, all other terms to the right

-2y=-13

y=-13/-2

y=6+1/2

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