3(y+2)+y=15-(y-4)

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Solution for 3(y+2)+y=15-(y-4) equation:


Simplifying
3(y + 2) + y = 15 + -1(y + -4)

Reorder the terms:
3(2 + y) + y = 15 + -1(y + -4)
(2 * 3 + y * 3) + y = 15 + -1(y + -4)
(6 + 3y) + y = 15 + -1(y + -4)

Combine like terms: 3y + y = 4y
6 + 4y = 15 + -1(y + -4)

Reorder the terms:
6 + 4y = 15 + -1(-4 + y)
6 + 4y = 15 + (-4 * -1 + y * -1)
6 + 4y = 15 + (4 + -1y)

Combine like terms: 15 + 4 = 19
6 + 4y = 19 + -1y

Solving
6 + 4y = 19 + -1y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add 'y' to each side of the equation.
6 + 4y + y = 19 + -1y + y

Combine like terms: 4y + y = 5y
6 + 5y = 19 + -1y + y

Combine like terms: -1y + y = 0
6 + 5y = 19 + 0
6 + 5y = 19

Add '-6' to each side of the equation.
6 + -6 + 5y = 19 + -6

Combine like terms: 6 + -6 = 0
0 + 5y = 19 + -6
5y = 19 + -6

Combine like terms: 19 + -6 = 13
5y = 13

Divide each side by '5'.
y = 2.6

Simplifying
y = 2.6

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