3(y+2)+y=26

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Solution for 3(y+2)+y=26 equation:



3(y+2)+y=26
We move all terms to the left:
3(y+2)+y-(26)=0
We add all the numbers together, and all the variables
y+3(y+2)-26=0
We multiply parentheses
y+3y+6-26=0
We add all the numbers together, and all the variables
4y-20=0
We move all terms containing y to the left, all other terms to the right
4y=20
y=20/4
y=5

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