3(y+2)+y=4(y-1)+10

Solution for 3(y+2)+y=4(y-1)+10 equation:

Simplifying
3(y + 2) + y = 4(y + -1) + 10

Reorder the terms:
3(2 + y) + y = 4(y + -1) + 10
(2 * 3 + y * 3) + y = 4(y + -1) + 10
(6 + 3y) + y = 4(y + -1) + 10

Combine like terms: 3y + y = 4y
6 + 4y = 4(y + -1) + 10

Reorder the terms:
6 + 4y = 4(-1 + y) + 10
6 + 4y = (-1 * 4 + y * 4) + 10
6 + 4y = (-4 + 4y) + 10

Reorder the terms:
6 + 4y = -4 + 10 + 4y

Combine like terms: -4 + 10 = 6
6 + 4y = 6 + 4y

Add '-6' to each side of the equation.
6 + -6 + 4y = 6 + -6 + 4y

Combine like terms: 6 + -6 = 0
0 + 4y = 6 + -6 + 4y
4y = 6 + -6 + 4y

Combine like terms: 6 + -6 = 0
4y = 0 + 4y
4y = 4y

Add '-4y' to each side of the equation.
4y + -4y = 4y + -4y

Combine like terms: 4y + -4y = 0
0 = 4y + -4y

Combine like terms: 4y + -4y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.