3(y+2)+y=4(y-1)+9

Solution for 3(y+2)+y=4(y-1)+9 equation:

Simplifying
3(y + 2) + y = 4(y + -1) + 9

Reorder the terms:
3(2 + y) + y = 4(y + -1) + 9
(2 * 3 + y * 3) + y = 4(y + -1) + 9
(6 + 3y) + y = 4(y + -1) + 9

Combine like terms: 3y + y = 4y
6 + 4y = 4(y + -1) + 9

Reorder the terms:
6 + 4y = 4(-1 + y) + 9
6 + 4y = (-1 * 4 + y * 4) + 9
6 + 4y = (-4 + 4y) + 9

Reorder the terms:
6 + 4y = -4 + 9 + 4y

Combine like terms: -4 + 9 = 5
6 + 4y = 5 + 4y

Add '-4y' to each side of the equation.
6 + 4y + -4y = 5 + 4y + -4y

Combine like terms: 4y + -4y = 0
6 + 0 = 5 + 4y + -4y
6 = 5 + 4y + -4y

Combine like terms: 4y + -4y = 0
6 = 5 + 0
6 = 5

Solving
6 = 5

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.