3(y+2)+y=4(y-1)=10

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Solution for 3(y+2)+y=4(y-1)=10 equation: 



3(y+2)+y=4(y-1)=10

We move all terms to the left:

3(y+2)+y-(4(y-1))=0

We add all the numbers together, and all the variables

y+3(y+2)-(4(y-1))=0

We multiply parentheses

y+3y-(4(y-1))+6=0



We calculate terms in parentheses: -(4(y-1)), so:

4(y-1)

We multiply parentheses

4y-4

Back to the equation:

-(4y-4)



We add all the numbers together, and all the variables

4y-(4y-4)+6=0

We get rid of parentheses

4y-4y+4+6=0

We add all the numbers together, and all the variables

10!=0

There is no solution for this equation

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