3(y+2)+y=4(y-1+9

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Solution for 3(y+2)+y=4(y-1+9 equation: 



3(y+2)+y=4(y-1+9

We move all terms to the left:

3(y+2)+y-(4(y-1+9)=0

We add all the numbers together, and all the variables

3(y+2)+y-(4(y+8)=0

We add all the numbers together, and all the variables

y+3(y+2)-(4(y+8)=0

We multiply parentheses

y+3y-(4(y+8)+6=0

We add all the numbers together, and all the variables

4y-(4(y+8)+6=0

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