3(y+2)-16=18y

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Solution for 3(y+2)-16=18y equation:



3(y+2)-16=18y
We move all terms to the left:
3(y+2)-16-(18y)=0
We add all the numbers together, and all the variables
-18y+3(y+2)-16=0
We multiply parentheses
-18y+3y+6-16=0
We add all the numbers together, and all the variables
-15y-10=0
We move all terms containing y to the left, all other terms to the right
-15y=10
y=10/-15
y=-2/3

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