3(y+2)-16=18y

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Solution for 3(y+2)-16=18y equation: 



3(y+2)-16=18y

We move all terms to the left:

3(y+2)-16-(18y)=0

We add all the numbers together, and all the variables

-18y+3(y+2)-16=0

We multiply parentheses

-18y+3y+6-16=0

We add all the numbers together, and all the variables

-15y-10=0

We move all terms containing y to the left, all other terms to the right

-15y=10

y=10/-15

y=-2/3

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